Showing posts with label Engineering. Show all posts
Showing posts with label Engineering. Show all posts

Wednesday, November 9, 2011

Best thing about civil engineering

Recently i read a post somewhere in computer coding forum by some computer engineer. It read as follows:


".....


a = 5


b = 10


a = b


print a


You look at the code above and aren't sure what number gets printed out at the end


Alternative careers


Electrician


Plumber


Architect


Civil engineer


..........."


This is purely under estimated comment.Stupid people like him is creating some stupid softwares without puting his brain on use or knowing what the equation means in real life. And still they think they are really smart.


Lets see where he will not find a civil engineer or an architect..


the house he lives is designed by the architect and enforced by civil engineer .


the water he drinks will come from a soruce far away using system of channels, pipes, crossings..civil engnieer is supposed to get him that water even in draught!


the electriciy which he utilizes comes from the dam built by civil engineer and transmission line errected by civil engineers..


the road and bridges which he uses to go his home and office is built by civil engineers


the airport which he uses to fly his plane is built by civil engineers


the waste he generates in his lifetime is dispossed in secure way by civil engineers


the food he eats gets nutured from the water diverted by a civil engineer.




By copying and pasting the code you can easily be a computer engineer. F*** off. We know how to do our works.


Do you know how computers are used by civil engineer to put stupid people like you in comfort?


They use it to design the nuclear plant.


They use it to make dams and bridges.


They use it to design your gas pipes.


They use it to get answer of those things which you will never understand..


They use it to design the factories where your clothes are woven ..( wont you be shameful!)


I am and will be a civil engineer.


And if still you think you are clearver,


Do you know how high is your street light?


Do you know how many seconds red light glows in zebra crossing?


Do you know why your house do not break even by earthquake?




......


spread love not hate..

Wednesday, June 8, 2011

Indian Standard Steel Table

The collection of all the steel sections used in structural design of steel structure is given here. Download the excel data file. It contains Excel file containing all the steel sections used in Indian standard (IS). It will be very useful to all the steel designers.




























































angle.JPG














Angle section



















box.JPG














Tube section



















channel.JPG














Channel section



















i.JPG














I section



















pipe.JPG














Pipe section










Friday, May 27, 2011

Civil structures Ghunsa microhydro project (GMP).

The microhydro plant consists essentially of the all the components that a bigger hydropower plant will consist of. This article will try to give real impression of what micro hydro plant will look like in the field after construction.Ghunsa microhydro project has been used in this article. This project is located at an elevation of 3500m above sea level at Taplejung district of Nepal. The plant generates 35Kw.


DSC06717.JPG




Intake, gravel trap and settling basin.

Intake consists of a chamber to collect water. A gravel trap is generally provided to exclude coarse sediment to enter the water way. If water has sediments that need to be addressed, then a settling basin is also provided. The inake of GMP is at the right bank of Yamatari river. The water gets frozen in winter season. Settling basin has not been provided in this project as the water qualtiy is good.



















Intake stucture




River protection for intake



intake gate.JPG


Intake gate




Gravel trap flushing




Trashrack at intake




Gravel trap after the intake



Waterways

The waterways consists of canal joining intake and forebay. Depending upon the topography, the canal is in filling or cutting as shown in the figures.














Canal in cutting




Canal in filling. (Notice seepage!)




Canal in cutting




Forebay

Forebay is a water tank to hold water for specific time. The water from forebay is then tranmitted to powerhouse using penstock pipes. The forebay consists of a spillway to divert excess water. This maintains constant head (elevation of water) for the trubines in the powerhouse.










The forebay with spillway in the left. It also consist of pipe spillway at the center.



Penstock pipes

Penstock pipes transmitts the flow from forebay to powerhouse. Saddle support and anchor blocks are provided to hold the penstock in the fixed alignment.











Penstock alignment




Anchor block in penstock alignment



Powerhouse and tailrace

The flow from penstock strikes the turbine and generator produces electricity. The flow is then discharged back to original river. The powehouse of GMP is near the southern end of Ghunsa village.


















Powerhouse




Penstock inlet at powerhouse




The penstock inside the powerhouse




Turbine




Powerhouse with tailrace outlet



Most efficient trapezoidal section of canal

The most efficient trapezoidal section of canal can be calculated as follows




canal section.JPG


Let,


Base width of the canal=B


Side slope=m (1V:mH)


Flow depth = h


Wetted perimeter= P


The cross sectional area, A=By+my^2


ie B= (A-m*h^2)/h


ie B=A/h-m*h


Wetted perimeter P= B+2*h *sqrt(m^2+1)


For most efficient channel, dP/dh=0


ie -A-m*y^2+2 y^2 sqrt(m^2+1)=0


ie B= y(2*sqrt(m2+1)-1-m)


Therfoer B/y=2*sqrt(m2+1)-1-m is the required relationship


Elementary analysis for width/height ratio of retaining masonary structure

As we know that masonry structure cannot resist tension, hence all the lateral force should be resisted by its weight component only. In this article we will derive expression for width/height ratio for a simple rectangular masonry structure.


force.jpg


Let,


γ=density of water


Sm=specific gravity of masonry material


SL=specific gravity of material giving lateral force (e.g. water, soil etc)


h=height of the structure


x=width of the structure


W=weight of structure=h*x*s* γ


μ= coefficient of friction


Case1: For overturning


Moment dut to lateral force=moment due to weight of the material


½* γ*sL*h2*h/3 =W*x/2


Or, ½* γ*h2*h/3*sL = γ *sm*h*x*x/2


Or, (x/h)2=(sL/(3*sm))


Or, x/h=sqrt(sL/sm/3)


For water sL=1;for stone masonry sm=22/9.81=2.14


Therefore, x/h=0.394≈0.4


Case2: For Sliding


Horizontal force=friction factor*weight of the structure


½* γ*sL*h2= μ (γ*sm*h*x)


Or, x/h=sL/(2*sm* μ)


For water and stone masonry and using μ=0.65


x/h=0.359≈0.4



Thus from above derivation we see that the minimum base width/height ratio of the rectangular block to resist the lateral (triangular here) force with safety factor 1 is 0.4.


With safety factor of 1.5 the minimum width/height ratio becomes 1.5*0.4=0.6.





Derivation of Combined Angle


Abstract: Derivation of combined angle may become useful when you want to know the magnitude and direction of force due to bend in both XY and XZ plane. For eg in design of bend in pipeline.


Let us consider a straight line which deflects at O along OA as shown in the figure. The deflection angles are also shown in the figure.


Let R be the position vector of A. OB is projection of OA on XY plane and AB is projection of OA on a plane parallel to YZ plane. Similarly, OC is projection of line OB in X axis and BC is projection of OB on axis parallel to Y axis.


From figure it can inferred that


OB=R cosα


AB=R sinα


OC=OB cosβ = R cosα cosβ


BC= OB sinβ =R cosα sinβ


Therefore, the position vector of A is OA which is given by


R=|R| (cosα cosβ i + cosα sinβ j + sinα k )


And the unit vector along R is given by


r= (cosα cosβ i + cosα sinβ j + sinα k )


Now the combined deflection angle is given by


r . i =|r| |i| cosδ


Or, r . i =1*1 cosδ


Or, cosδ = cosα cosβ+0+0


Or, δ =cos-1(cosα cosβ)


The angle δ lies in the plane OAC. This plane is shown in the figure in hatch line.


Forces


If F be the magnitude of force due to the deflection δ (e.g. deflection in pipeline) then the vertical and horizontal component of this force is given by,


Fx1 =F r . i =F cosα cosβ


Fx2 =F r . j =F cosα sinβ


Fx =F


=F cosα


Fy =F r . j


=F sinα

Sunday, September 12, 2010

MEASUREMENT OF LAND IN NEPAL

In Nepal we use different units for measurement of land. In hilly regions we use Ropani-Ana-Paisa-Dam system while in Southern parts i.e. at Terai region we use Bhigha-Kattha-Dhur system.






The conversion between these units and also to the SI unit is essential as we come across this situation often.






The conversion factor for these units is as follows






Ropani-Ana-Paisa-Dam system














  • 1 Ropani =16Ana












  • 1 Ana =4 Paisa












  • 1Paisa =4 Dam














Bhigha-Kattha-Dhur system














  • 1 Bhigha= 20 Kattha












  • 1 Kattha= 20 Dhur














For inter conversion between Ropani and Bhigha














  • 1Bhigha=13 Ropani














Similarly in standard units we may use














  • 1 Ropani =74feet X 74 feet












  • 1 m=3.218 feet














An Excel sheet has been developed for the general use which can be downloaded in this page.